Khanh at 21:38, 15 January 2022

2022-01-15T21:38:28Z

Lila: /* Resources */

2021-10-27T21:06:49Z

Resources

Lila at 22:21, 29 September 2021

2021-09-29T22:21:47Z

James.kercheville: Added links for PowerPoint and worksheet

2020-08-13T23:17:53Z

Added links for PowerPoint and worksheet

New page

* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRulePwPt.pptx The Chain Rule] PowerPoint file created by Dr. Sara Shirinkam, UTSA.

* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRuleWS1.pdf The Chain Rule Worksheet]

@@ Line 14: / Line 14: @@
 |}
-The method is called the "chain rule" because it can be applied sequentially to as many functions as are nested inside one another. <ref>http://www.math.brown.edu/help/derivtips.html</ref> For example, if <math>f</math> is a function of <math>g</math> which is in turn a function of <math>h</math> , which is in turn a function of <math>x</math> , that is
+The method is called the "chain rule" because it can be applied sequentially to as many functions as are nested inside one another. For example, if <math>f</math> is a function of <math>g</math> which is in turn a function of <math>h</math> , which is in turn a function of <math>x</math> , that is
 :<math>f\bigl(g(h(x))\bigr)</math>
 the derivative of <math>f</math> with respect to <math>x</math> is given by
@@ Line 111: / Line 111: @@
 | <math>\frac{df}{dx}=\frac{df}{dg}\cdot\frac{dg}{dh}\cdot\frac{dh}{dx}</math> || Express chain rule applicable here
 |-
-| <math>\frac{df}{dg}=e^g=e^{\sin(x^2)}</math> || Differentiate f(g)<ref>The derivative of <math>e^x</math> is <math>e^x</math> ; see [[../Derivatives of Exponential and Logarithm Functions]].</ref>
+| <math>\frac{df}{dg}=e^g=e^{\sin(x^2)}</math> || Differentiate f(g)
 |-
 | <math>\frac{dg}{dh}=\cos(h)=\cos(x^2)</math> || Differentiate <math>g(h)</math>

← Older revision		Revision as of 21:06, 27 October 2021
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	* [https://en.wikibooks.org/wiki/Calculus/Chain_Rule Chain Rule], WikiBooks Calculus		* [https://en.wikibooks.org/wiki/Calculus/Chain_Rule Chain Rule], WikiBooks Calculus
		+
		+	==Licensing==
		+	Content obtained and/or adapted from:
		+	* [https://en.wikibooks.org/wiki/Calculus/Chain_Rule Chain Rule, WikiBooks: Calculus] under a CC BY-SA license

← Older revision		Revision as of 22:21, 29 September 2021
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		+	The '''chain rule''' is a method to compute the derivative of the functional composition of two or more functions.
		+
		+	If a function <math>f</math> depends on a variable <math>u</math> , which in turn depends on another variable <math>x</math> , that is <math>f=y\bigl(u(x)\bigr)</math> , then the rate of change of <math>f</math> with respect to <math>x</math> can be computed as the rate of change of <math>y</math> with respect to <math>u</math> multiplied by the rate of change of <math>u</math> with respect to <math>x</math> .
		+
		+	{\| WIDTH="75%"
		+	\|-
		+	\| style="background-color: #FFFFFF; border: solid 1px #D6D6FF; padding: 1em;" valign="top" \|
		+	<center>'''Chain Rule'''<br>
		+	If a function <math>f</math> is composed to two differentiable functions <math>y(x)</math> and <math>u(x)</math> , so that <math>f(x)=y\bigl(u(x)\bigr)</math> , then <math>f(x)</math> is differentiable and,
		+
		+	<math>\frac{df}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}</math>
		+
		+	</center>
		+	\|}
		+
		+	The method is called the "chain rule" because it can be applied sequentially to as many functions as are nested inside one another. <ref>http://www.math.brown.edu/help/derivtips.html</ref> For example, if <math>f</math> is a function of <math>g</math> which is in turn a function of <math>h</math> , which is in turn a function of <math>x</math> , that is
		+	:<math>f\bigl(g(h(x))\bigr)</math>
		+	the derivative of <math>f</math> with respect to <math>x</math> is given by
		+	:<math>\frac{df}{dx}=\frac{df}{dg}\cdot\frac{dg}{dh}\cdot\frac{dh}{dx}</math> and so on.
		+	A useful mnemonic is to think of the differentials as individual entities that can be canceled algebraically, such as
		+	:<math>\frac{df}{dx}=\frac{df}{\cancel{dg}}\cdot\frac{\cancel{dg}}{\cancel{dh}}\cdot\frac{\cancel{dh}}{dx}</math>
		+	However, keep in mind that this trick comes about through a clever choice of notation rather than through actual algebraic cancellation.
		+
		+	The chain rule has broad applications in physics, chemistry, and engineering, as well as being used to study related rates in many disciplines. The chain rule can also be generalized to multiple variables in cases where the nested functions depend on more than one variable.
		+
		+	==Examples==
		+	===Example I===
		+	Suppose that a mountain climber ascends at a rate of <math>0.5\frac{km}{h}</math> . The temperature is lower at higher elevations; suppose the rate by which it decreases is <math>6^\circ C</math> per kilometer. To calculate the decrease in air temperature per hour that the climber experiences, one multiplies <math>\frac{6^\circ C}{km}</math> by <math>0.5\frac{km}{h}</math> , to obtain <math>\frac{3^\circ C}{h}</math> . This calculation is a typical chain rule application.
		+
		+	===Example II===
		+	Consider the function <math>f(x)=(x^2+1)^3</math> . It follows from the chain rule that
		+
		+	{\| cellpadding=5
		+	\|-
		+	\| <math>f(x)=(x^2+1)^3</math> \|\| width="250pt" \|Function to differentiate
		+	\|-
		+	\| <math>u(x)=x^2+1</math> \|\| Define <math>u(x)</math> as inside function
		+	\|-
		+	\| <math>f(x)=u(x)^3</math> \|\| Express <math>f(x)</math> in terms of <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{df}{du}\cdot\frac{du}{dx}</math> \|\| Express chain rule applicable here
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{d}{du}u^3\cdot\frac{d}{dx}(x^2+1)</math> \|\| Substitute in <math>f(u)</math> and <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=3u^2\cdot2x</math> \|\| Compute derivatives with power rule
		+	\|-
		+	\| <math>\frac{df}{dx}=3(x^2+1)^2\cdot 2x</math> \|\| Substitute <math>u(x)</math> back in terms of <math>x</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=6x(x^2+1)^2</math> \|\| Simplify.
		+	\|}
		+
		+	===Example III===
		+	In order to differentiate the trigonometric function
		+	:<math>f(x)=\sin(x^2)</math>
		+	one can write:
		+
		+	{\| cellpadding=5
		+	\|-
		+	\| <math>f(x)=\sin(x^2)</math> \|\| width="250pt" \|Function to differentiate
		+	\|-
		+	\| <math>u(x)=x^2</math> \|\| Define <math>u(x)</math> as inside function
		+	\|-
		+	\| <math>f(x)=\sin(u)</math> \|\| Express <math>f(x)</math> in terms of <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{df}{du}\cdot\frac{du}{dx}</math> \|\| Express chain rule applicable here
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{d}{du}\sin(u)\cdot\frac{d}{dx}(x^2)</math> \|\| Substitute in <math>f(u)</math> and <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\cos(u)\cdot 2x</math> \|\| Evaluate derivatives
		+	\|-
		+	\| <math>\frac{df}{dx}=\cos(x^2)\cdot 2x</math> \|\| Substitute <math>u</math> in terms of <math>x</math> .
		+	\|}
		+
		+	===Example IV: absolute value===
		+	The chain rule can be used to differentiate <math>\|x\|</math> , the absolute value function:
		+
		+	{\| cellpadding=5
		+	\|-
		+	\| <math>f(x)=\|x\|</math> \|\| width="250pt" \|Function to differentiate
		+	\|-
		+	\| <math>f(x)=\sqrt{x^2}</math> \|\| Equivalent function
		+	\|-
		+	\| <math>u(x)=x^2</math> \|\| Define <math>u(x)</math> as inside function
		+	\|-
		+	\| <math>f(x)=u(x)^\frac12</math> \|\| Express <math>f(x)</math> in terms of <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{df}{du}\cdot\frac{du}{dx}</math> \|\| Express chain rule applicable here
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{d}{du}u^\frac12\cdot\frac{d}{dx}(x^2)</math> \|\| Substitute in <math>f(u)</math> and <math>u(x)</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{u^{-\frac12}}{2}\cdot 2x</math> \|\| Compute derivatives with power rule
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{(x^2)^{-\frac12}}{2}\cdot 2x</math> \|\| Substitute <math>u(x)</math> back in terms of <math>x</math>
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{x}{\sqrt{x^2}}</math> \|\| Simplify
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{x}{\|x\|}</math> \|\| Express <math>\sqrt{x^2}</math> as absolute value.
		+	\|}
		+
		+	===Example V: three nested functions===
		+	The method is called the "chain rule" because it can be applied sequentially to as many functions as are nested inside one another. For example, if <math>f\bigl(g(h(x))\bigr)=e^{\sin(x^2)}</math> , sequential application of the chain rule yields the derivative as follows (we make use of the fact that <math>\frac{d}{dx}e^x=e^x</math> , which will be proved in a later section):
		+
		+	{\| cellpadding=5
		+	\|-
		+	\| <math>f(x)=e^{\sin(x^2)}=e^g</math> \|\| width="250pt" \|Original (outermost) function
		+	\|-
		+	\| <math>h(x)=x^2</math> \|\| Define <math>h(x)</math> as innermost function
		+	\|-
		+	\| <math>g(x)=\sin(h)=\sin(x^2)</math> \|\| <math>g(h)=sin(h)</math> as middle function
		+	\|-
		+	\| <math>\frac{df}{dx}=\frac{df}{dg}\cdot\frac{dg}{dh}\cdot\frac{dh}{dx}</math> \|\| Express chain rule applicable here
		+	\|-
		+	\| <math>\frac{df}{dg}=e^g=e^{\sin(x^2)}</math> \|\| Differentiate f(g)<ref>The derivative of <math>e^x</math> is <math>e^x</math> ; see [[../Derivatives of Exponential and Logarithm Functions]].</ref>
		+	\|-
		+	\| <math>\frac{dg}{dh}=\cos(h)=\cos(x^2)</math> \|\| Differentiate <math>g(h)</math>
		+	\|-
		+	\| <math>\frac{dh}{dx}=2x</math> \|\| Differentiate <math>h(x)</math>
		+	\|-
		+	\| <math>\frac{d}{dx}e^{\sin(x^2)}= e^{\sin(x^2)}\cdot\cos(x^2)\cdot 2x</math> \|\| Substitute into chain rule.
		+	\|}
		+
		+	==Proof of the chain rule==
		+	Suppose <math>y</math> is a function of <math>u</math> which is a function of <math>x</math> (it is assumed that <math>y</math> is differentiable at <math>u</math> and <math>x</math> , and <math>u</math> is differentiable at <math>x</math> .
		+	To prove the chain rule we use the definition of the derivative.
		+	:<math>\frac{dy}{dx}=\lim_{\Delta x\to0}\frac{\Delta y}{\Delta x}</math>
		+	We now multiply <math>\frac{\Delta y}{\Delta x}</math> by <math>\frac{\Delta u}{\Delta u}</math> and perform some algebraic manipulation.
		+	:<math>\lim_{\Delta x\to0}\frac{\Delta y}{\Delta x}=\lim_{\Delta x\to0}\frac{\Delta y}{\Delta u}\cdot\frac{\Delta u}{\Delta x}=\lim_{\Delta x\to0}\frac{\Delta y}{\Delta u}\cdot\lim_{\Delta x\to0}\frac{\Delta u}{\Delta x}=\lim_{\Delta x\to0}\frac{\Delta y}{\Delta u}\cdot\frac{du}{dx}</math>
		+
		+	Note that as <math>\Delta x</math> approaches <math>0</math> , <math>\Delta u</math> also approaches <math>0</math> . So taking the limit as of a function as <math>\Delta x</math> approaches <math>0</math> is the same as taking its limit as <math>\Delta u</math> approaches <math>0</math> . Thus
		+	:<math>\lim_{\Delta x\to0}\frac{\Delta y}{\Delta u}=\lim_{\Delta u\to0}\frac{\Delta y}{\Delta u}=\frac{dy}{du}</math>
		+	So we have
		+	:<math>\frac{dy}{dx}=\frac{dy}{du}\cdot\frac{du}{dx}</math>
		+
		+
		+
		+	==Resources==
	* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRulePwPt.pptx The Chain Rule] PowerPoint file created by Dr. Sara Shirinkam, UTSA.		* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRulePwPt.pptx The Chain Rule] PowerPoint file created by Dr. Sara Shirinkam, UTSA.

	* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRuleWS1.pdf The Chain Rule Worksheet]		* [https://mathresearch.utsa.edu/wikiFiles/MAT1214/The%20Chain%20Rule_/MAT1214-3.6TheChainRuleWS1.pdf The Chain Rule Worksheet]
		+
		+	* [https://en.wikibooks.org/wiki/Calculus/Chain_Rule Chain Rule], WikiBooks Calculus

Chain Rule - Revision history

Khanh at 21:38, 15 January 2022

Lila: /* Resources */

Lila at 22:21, 29 September 2021

James.kercheville: Added links for PowerPoint and worksheet