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	<id>https://mathresearch.utsa.edu/wiki/index.php?action=history&amp;feed=atom&amp;title=The_Nested_Interval_Theorem_in_Higher_Dimensions</id>
	<title>The Nested Interval Theorem in Higher Dimensions - Revision history</title>
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	<updated>2026-04-09T15:51:45Z</updated>
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		<id>https://mathresearch.utsa.edu/wiki/index.php?title=The_Nested_Interval_Theorem_in_Higher_Dimensions&amp;diff=3801&amp;oldid=prev</id>
		<title>Khanh at 22:29, 13 November 2021</title>
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		<updated>2021-11-13T22:29:23Z</updated>

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&lt;table class=&quot;diff diff-contentalign-left&quot; data-mw=&quot;interface&quot;&gt;
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				&lt;td colspan=&quot;2&quot; style=&quot;background-color: #fff; color: #222; text-align: center;&quot;&gt;← Older revision&lt;/td&gt;
				&lt;td colspan=&quot;2&quot; style=&quot;background-color: #fff; color: #222; text-align: center;&quot;&gt;Revision as of 22:29, 13 November 2021&lt;/td&gt;
				&lt;/tr&gt;&lt;tr&gt;&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot; id=&quot;mw-diff-left-l20&quot; &gt;Line 20:&lt;/td&gt;
&lt;td colspan=&quot;2&quot; class=&quot;diff-lineno&quot;&gt;Line 20:&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;We have just looked at what exactly a Nested Interval is, and we are about to look at a critically important theorem in Real Analysis. Before we look at the Nested Intervals Theorem let's first look at the following important lemma that will be used to prove the Nested Intervals Theorem.&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;We have just looked at what exactly a Nested Interval is, and we are about to look at a critically important theorem in Real Analysis. Before we look at the Nested Intervals Theorem let's first look at the following important lemma that will be used to prove the Nested Intervals Theorem.&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt; &lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;:'''Lemma 1:''' Let &amp;lt;math&amp;gt;a &amp;lt; b&amp;lt;/math&amp;gt; and let &amp;lt;math&amp;gt;c &amp;lt; d&amp;lt;/math&amp;gt; and let &amp;lt;math&amp;gt;I = [a, b]&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;J = [c, d]&amp;lt;/math&amp;gt;. Then &amp;lt;math&amp;gt;I \subseteq J&amp;lt;/math&amp;gt; if and only if &amp;lt;math&amp;gt;c \leq a &amp;lt; b \leq d&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;/blockquote&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;Now let's look at the Nested Intervals theorem.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt; &lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;'''Theorem 1:''' If the interval &amp;lt;math&amp;gt;I_n = [a_n, b_n]&amp;lt;/math&amp;gt; for &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; is a sequence of closed bounded nested intervals then there exists a real number &amp;lt;math&amp;gt;\xi = \sup \{ a_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;\xi \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;/blockquote&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*'''Proof of Theorem:''' We note that by the definition of nested intervals that &amp;lt;math&amp;gt;I_n \subseteq I_1&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; so then &amp;lt;math&amp;gt;a_n \leq b_1&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;	&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*Now consider the nonempty set &amp;lt;math&amp;gt;A = \{ a_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; that is bounded above by &amp;lt;math&amp;gt;b_1&amp;lt;/math&amp;gt;. Thus this set has a supremum in the real numbers and denote it &amp;lt;math&amp;gt;\sup A = \xi&amp;lt;/math&amp;gt; so that &amp;lt;math&amp;gt;a_n \leq\xi&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*We now want to show that &amp;lt;math&amp;gt;\xi \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. We will do this by showing that &amp;lt;math&amp;gt;a_n \leq b_k&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n, k \in \mathbb{N}&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;		&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*First consider the case where &amp;lt;math&amp;gt;n \leq k&amp;lt;/math&amp;gt;. We thus have that &amp;lt;math&amp;gt;I_n \supseteq I_k&amp;lt;/math&amp;gt; by the definition of nested intervals and so by lemma 1 we get that &amp;lt;math&amp;gt;a_n \leq a_k \leq b_k \leq b_n&amp;lt;/math&amp;gt;. Here we see that &amp;lt;math&amp;gt;a_n \leq b_k&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;	&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*Now consider the case where &amp;lt;math&amp;gt;n &amp;gt; k&amp;lt;/math&amp;gt;. We thus have that &amp;lt;math&amp;gt;I_k \supseteq I_n&amp;lt;/math&amp;gt; by the definition of nested intervals and so by lemma 1 once again we have that &amp;lt;math&amp;gt;a_k \leq a_n \leq b_n \leq b_k&amp;lt;/math&amp;gt;. Once again we have that &amp;lt;math&amp;gt;a_n \leq b_k&amp;lt;/math&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;	&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*So then &amp;lt;math&amp;gt;a_n \leq b_k&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n, k \in \mathbb{N}&amp;lt;/math&amp;gt;, and so &amp;lt;math&amp;gt;b_k&amp;lt;/math&amp;gt; is an upper bound to the set &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;\sup A = \xi \leq b_k&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt;. Furthermore we have that &amp;lt;math&amp;gt;a_k \leq \xi&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt;, and so &amp;lt;math&amp;gt;\xi \in I_k&amp;lt;/math&amp;gt; for every &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt; and thus &amp;lt;math&amp;gt;\xi \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt; and so the set theoretic union is nonempty. &amp;lt;math&amp;gt;\blacksquare&amp;lt;/math&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt; &lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;'''Theorem 2:''' If the interval &amp;lt;math&amp;gt;I_n = [a_n, b_n]&amp;lt;/math&amp;gt; for &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; is a sequence of closed bounded nested intervals then there exists a real number &amp;lt;math&amp;gt;\eta = \inf \{ b_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;\eta \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;/blockquote&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*'''Proof:''' We note that by the definition of nested intervals that &amp;lt;math&amp;gt;I_n \subseteq I_1&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; so then &amp;lt;math&amp;gt;a_1 \leq b_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*Now consider the nonempty set &amp;lt;math&amp;gt;B = \{ b_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; that is bounded below by &amp;lt;math&amp;gt;a_1&amp;lt;/math&amp;gt;. Thus this set has an infimum in the real numbers and denote it &amp;lt;math&amp;gt;\inf B = \eta&amp;lt;/math&amp;gt; so that &amp;lt;math&amp;gt;\eta \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*We now want to show that &amp;lt;math&amp;gt;a_n \leq \eta&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. We will do this by showing that &amp;lt;math&amp;gt;a_k \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n, k \in \mathbb{N}&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*First consider the case where &amp;lt;math&amp;gt;n \leq k&amp;lt;/math&amp;gt;. We thus have that &amp;lt;math&amp;gt;I_n \supseteq I_k&amp;lt;/math&amp;gt; by the definition of nested intervals and so by lemma 1 we get that &amp;lt;math&amp;gt;a_n \leq a_k \leq b_k \leq b_n&amp;lt;/math&amp;gt;. Here we see that &amp;lt;math&amp;gt;a_k \leq b_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*Now consider the case where &amp;lt;math&amp;gt;n &amp;gt; k&amp;lt;/math&amp;gt;. We thus have that &amp;lt;math&amp;gt;I_k \supseteq I_n&amp;lt;/math&amp;gt; by the definition of nested intervals and so by lemma 1 once again we have that &amp;lt;math&amp;gt;a_k \leq a_n \leq b_n \leq b_k&amp;lt;/math&amp;gt;. Once again we have that &amp;lt;math&amp;gt;a_k \leq b_n&amp;lt;/math&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*So then &amp;lt;math&amp;gt;a_k \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n, k \in \mathbb{N}&amp;lt;/math&amp;gt;, and so &amp;lt;math&amp;gt;a_k&amp;lt;/math&amp;gt; is an upper bound to the set &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;a_k \leq \eta = \inf B&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt;. Furthermore we have that &amp;lt;math&amp;gt;\eta \leq b_k&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt;, and so &amp;lt;math&amp;gt;\eta \in I_k&amp;lt;/math&amp;gt; for every &amp;lt;math&amp;gt;k \in \mathbb{N}&amp;lt;/math&amp;gt; and thus &amp;lt;math&amp;gt;\eta \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;. &amp;lt;math&amp;gt;\blacksquare&amp;lt;/math&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt; &lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;:'''Theorem 3:''' Let &amp;lt;math&amp;gt;A := \{ a_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;B := \{ b_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt;. If &amp;lt;math&amp;gt;\sup A = \xi&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\inf B = \eta&amp;lt;/math&amp;gt; then if the interval &amp;lt;math&amp;gt;I_n = [a_n, b_n]&amp;lt;/math&amp;gt; is a sequence of closed bounded nested intervals then &amp;lt;math&amp;gt;[\xi, \eta] = \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&amp;lt;/blockquote&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*'''Proof:''' We first prove that &amp;lt;math&amp;gt;[\xi, \eta] \subseteq \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;. Now let &amp;lt;math&amp;gt;x \in [\xi, \eta] = \{ x \in \mathbb{R} : \xi \leq x \leq \eta&amp;lt;/math&amp;gt;. Therefore &amp;lt;math&amp;gt;\xi \leq x \leq \eta&amp;lt;/math&amp;gt;. But we know that &amp;lt;math&amp;gt;a_n \leq \xi&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; and we know that &amp;lt;math&amp;gt;\eta \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;a_n \leq \xi \leq x \leq \eta \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. Therefore &amp;lt;math&amp;gt;x \in [a_n, b_n]&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; or in other words &amp;lt;math&amp;gt;x \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;. Therefore &amp;lt;math&amp;gt;[\xi, \eta] \subseteq \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;	&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*We will now prove that &amp;lt;math&amp;gt;\bigcap_{n=1}^{\infty} I_n \subseteq [\xi, \eta]&amp;lt;/math&amp;gt;. Let &amp;lt;math&amp;gt;x \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;. Then &amp;lt;math&amp;gt;a_n \leq x \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. We also know that &amp;lt;math&amp;gt;a_n \leq \xi \leq \eta \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. Suppose that &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; is such that &amp;lt;math&amp;gt;a_n \leq x \leq \xi&amp;lt;/math&amp;gt;. Since &amp;lt;math&amp;gt;\xi&amp;lt;/math&amp;gt; is the supremum of the set &amp;lt;math&amp;gt;A&amp;lt;/math&amp;gt; then there exists an element &amp;lt;math&amp;gt;a_x \in \{ a_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;x &amp;lt; a_x&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;x \not \in [a_x, b_x]&amp;lt;/math&amp;gt; and therefore &amp;lt;math&amp;gt;x \not \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;, a contradiction. Now suppose that &amp;lt;math&amp;gt;x&amp;lt;/math&amp;gt; is such that &amp;lt;math&amp;gt;\eta \leq x \leq b_n&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. Since &amp;lt;math&amp;gt;\eta&amp;lt;/math&amp;gt; is the infimum of the set &amp;lt;math&amp;gt;B&amp;lt;/math&amp;gt; then there exists an element &amp;lt;math&amp;gt;b_x \in \{ b_n : n \in \mathbb{N} \}&amp;lt;/math&amp;gt; such that &amp;lt;math&amp;gt;b_x &amp;lt; x&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;x \not \in [a_x, b_x]&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;x \not \in \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;, once again, a contradiction. We must therefore have that &amp;lt;math&amp;gt;a_n \leq \xi \leq x \leq \eta \leq b_n&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;x \in [\xi, \eta]&amp;lt;/math&amp;gt; and so &amp;lt;math&amp;gt;\bigcap_{n=1}^{\infty} I_n \subseteq [\xi, \eta]&amp;lt;/math&amp;gt;.&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;*Since &amp;lt;math&amp;gt;[\xi, \eta] \subseteq \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\bigcap_{n=1}^{\infty} I_n \subseteq [\xi, \eta]&amp;lt;/math&amp;gt; we have that &amp;lt;math&amp;gt;[\xi, \eta] = \bigcap_{n=1}^{\infty} I_n&amp;lt;/math&amp;gt;. &amp;lt;math&amp;gt;\blacksquare&amp;lt;/math&amp;gt;&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;== Licensing ==  &lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;== Licensing ==  &lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;Content obtained and/or adapted from:&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;Content obtained and/or adapted from:&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;* [http://mathonline.wikidot.com/nested-intervals Nested Intervals, mathonline.wikidot.com] under a CC BY-SA license&lt;/div&gt;&lt;/td&gt;&lt;td class='diff-marker'&gt; &lt;/td&gt;&lt;td style=&quot;background-color: #f8f9fa; color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #eaecf0; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;* [http://mathonline.wikidot.com/nested-intervals Nested Intervals, mathonline.wikidot.com] under a CC BY-SA license&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;td colspan=&quot;2&quot;&gt; &lt;/td&gt;&lt;td class='diff-marker'&gt;+&lt;/td&gt;&lt;td style=&quot;color: #222; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;&quot;&gt;&lt;div&gt;&lt;ins style=&quot;font-weight: bold; text-decoration: none;&quot;&gt;* [http://mathonline.wikidot.com/the-nested-intervals-theorem The Nested Intervals Theorem, mathonline.wikidot.com] under a CC BY-SA license&lt;/ins&gt;&lt;/div&gt;&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;</summary>
		<author><name>Khanh</name></author>
		
	</entry>
	<entry>
		<id>https://mathresearch.utsa.edu/wiki/index.php?title=The_Nested_Interval_Theorem_in_Higher_Dimensions&amp;diff=3800&amp;oldid=prev</id>
		<title>Khanh: Created page with &quot;== Nested Intervals == &lt;blockquote style=&quot;background: white; border: 1px solid black; padding: 1em;&quot;&gt;  :'''Definition:''' A sequence of intervals &lt;math&gt;I_n&lt;/math&gt; where &lt;math&gt;...&quot;</title>
		<link rel="alternate" type="text/html" href="https://mathresearch.utsa.edu/wiki/index.php?title=The_Nested_Interval_Theorem_in_Higher_Dimensions&amp;diff=3800&amp;oldid=prev"/>
		<updated>2021-11-13T21:43:28Z</updated>

		<summary type="html">&lt;p&gt;Created page with &amp;quot;== Nested Intervals == &amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt;  :&amp;#039;&amp;#039;&amp;#039;Definition:&amp;#039;&amp;#039;&amp;#039; A sequence of intervals &amp;lt;math&amp;gt;I_n&amp;lt;/math&amp;gt; where &amp;lt;math&amp;gt;...&amp;quot;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;New page&lt;/b&gt;&lt;/p&gt;&lt;div&gt;== Nested Intervals ==&lt;br /&gt;
&amp;lt;blockquote style=&amp;quot;background: white; border: 1px solid black; padding: 1em;&amp;quot;&amp;gt; &lt;br /&gt;
:'''Definition:''' A sequence of intervals &amp;lt;math&amp;gt;I_n&amp;lt;/math&amp;gt; where &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt; is said to be '''[http://mathonline.wdfiles.com/local--files/nested-intervals/Screen%20Shot%202014-10-05%20at%207.37.43%20PM.png nested]'''if &amp;lt;math&amp;gt;I_1 \supseteq I_2 \supseteq I_3 \supseteq ... \supseteq I_n \supseteq I_{n+1} \supseteq ...&amp;lt;/math&amp;gt;.&lt;br /&gt;
&amp;lt;/blockquote&amp;gt;&lt;br /&gt;
&lt;br /&gt;
For example, consider the interval &amp;lt;math&amp;gt;I_n = [0, \frac{1}{n} ]&amp;lt;/math&amp;gt; We note that &amp;lt;math&amp;gt;I_1 = [0, 1]&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;I_2 = [0, \frac{1}{2}]&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;I_3 = [0, \frac{1}{3} ]&amp;lt;/math&amp;gt;, &amp;amp;#8230; As we can see &amp;lt;math&amp;gt;I_1 \supseteq I_2 \supseteq I_3 \supseteq ... \supseteq I_n \supseteq I_{n+1} \supseteq ...&amp;lt;/math&amp;gt; and so the sequence of intervals &amp;lt;math&amp;gt;I_n&amp;lt;/math&amp;gt; is nested. The diagram above illustrates this specific nesting of intervals.&lt;br /&gt;
	&lt;br /&gt;
Sometimes a nested interval will have a common point. In this specific example, the common point is &amp;lt;math&amp;gt;0&amp;lt;/math&amp;gt; since &amp;lt;math&amp;gt;0 \leq 0 &amp;lt; \frac{1}{n}&amp;lt;/math&amp;gt; for all &amp;lt;math&amp;gt;n \in \mathbb{N}&amp;lt;/math&amp;gt;. We denote the set theoretic intersection of all these intervals to be the set of common points in a nested set of intervals:&lt;br /&gt;
&lt;br /&gt;
&amp;lt;div style=&amp;quot;text-align: center;&amp;quot;&amp;gt;&amp;lt;math&amp;gt;\begin{align} \bigcap_{n=1}^{\infty} I_n = C \end{align}&amp;lt;/math&amp;gt;&amp;lt;/div&amp;gt;&lt;br /&gt;
	&lt;br /&gt;
Sometimes a set of nested intervals does not have a common point though. For example consider the set of intervals &amp;lt;math&amp;gt;I_n = (n, \infty)&amp;lt;/math&amp;gt;. Clearly &amp;lt;math&amp;gt;I_1 \supseteq I_2 \supseteq I_3 \supseteq ... \supseteq I_n \supseteq I_{n+1} \supseteq ...&amp;lt;/math&amp;gt; since &amp;lt;math&amp;gt;I_1 = (1, \infty)&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;I_2 = (2, \infty)&amp;lt;/math&amp;gt;, &amp;amp;#8230; However, there is no common point for these intervals.&lt;br /&gt;
	&lt;br /&gt;
===Example 1===&lt;br /&gt;
'''Determine the set &amp;lt;math&amp;gt;C&amp;lt;/math&amp;gt; of points to which the set of nested intervals &amp;lt;math&amp;gt;I_n = (1 - \frac{1}{n}, 2 + \frac{1}{n} )&amp;lt;/math&amp;gt; have in common.'''&lt;br /&gt;
	&lt;br /&gt;
We first note that &amp;lt;math&amp;gt;I_1 = [0, 3]&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;I_2 = [0.5, 2.5]&amp;lt;/math&amp;gt;, &amp;lt;math&amp;gt;I_3 = [0.66..., 2.33...]&amp;lt;/math&amp;gt;, &amp;amp;#8230; We conjecture that the set of points &amp;lt;math&amp;gt;C = \bigcap_{n=1}^{\infty} I_n = [1, 2]&amp;lt;/math&amp;gt; are contained within all the intervals. This can be informally deduced since &amp;lt;math&amp;gt;\lim_{n \to \infty} 1 - \frac{1}{n} = 1&amp;lt;/math&amp;gt; and &amp;lt;math&amp;gt;\lim_{n \to \infty} 2 + \frac{1}{n} = 2&amp;lt;/math&amp;gt;.&lt;br /&gt;
&lt;br /&gt;
== The Nested Intervals Theorem ==&lt;br /&gt;
&lt;br /&gt;
We have just looked at what exactly a Nested Interval is, and we are about to look at a critically important theorem in Real Analysis. Before we look at the Nested Intervals Theorem let's first look at the following important lemma that will be used to prove the Nested Intervals Theorem.&lt;br /&gt;
&lt;br /&gt;
== Licensing == &lt;br /&gt;
Content obtained and/or adapted from:&lt;br /&gt;
* [http://mathonline.wikidot.com/nested-intervals Nested Intervals, mathonline.wikidot.com] under a CC BY-SA license&lt;/div&gt;</summary>
		<author><name>Khanh</name></author>
		
	</entry>
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