Difference between revisions of "Baire's Theorem and Applications"
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| − | + | ===The Baire Category Theorem=== | |
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<td><strong>Lemma 1:</strong> Let <span class="math-inline"><math>(X, \tau)</math></span> be a topological space and let <span class="math-inline"><math>A \subseteq X</math></span>. If <span class="math-inline"><math>A</math></span> is a nowhere dense set then for every <span class="math-inline"><math>U \in \tau</math></span> there exists a <span class="math-inline"><math>B \subseteq U</math></span> such that <span class="math-inline"><math>A \cap \bar{B} = \emptyset</math></span>.</td> | <td><strong>Lemma 1:</strong> Let <span class="math-inline"><math>(X, \tau)</math></span> be a topological space and let <span class="math-inline"><math>A \subseteq X</math></span>. If <span class="math-inline"><math>A</math></span> is a nowhere dense set then for every <span class="math-inline"><math>U \in \tau</math></span> there exists a <span class="math-inline"><math>B \subseteq U</math></span> such that <span class="math-inline"><math>A \cap \bar{B} = \emptyset</math></span>.</td> | ||
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<li>Since <span class="math-inline"><math>x \in \bar{B_n}</math></span> for all <span class="math-inline"><math>n \in \mathbb{N}</math></span> then since <span class="math-inline"><math>A_n \cap \bar{B_n} = \emptyset</math></span> we must have that then <span class="math-inline"><math> x \not\in A_n </math></span></li> | <li>Since <span class="math-inline"><math>x \in \bar{B_n}</math></span> for all <span class="math-inline"><math>n \in \mathbb{N}</math></span> then since <span class="math-inline"><math>A_n \cap \bar{B_n} = \emptyset</math></span> we must have that then <span class="math-inline"><math> x \not\in A_n </math></span></li> | ||
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| + | ==Licensing== | ||
| + | Content obtained and/or adapted from: | ||
| + | * [http://mathonline.wikidot.com/the-baire-category-theorem The Baire Category Theorem, mathonline.wikidot.com] under a CC BY-SA license | ||
Revision as of 14:31, 8 November 2021
The Baire Category Theorem
Lemma 1: Let be a topological space and let . If is a nowhere dense set then for every there exists a such that .
Theorem 1 (The Baire Category Theorem): Every complete metric space is of the second category.
- Proof: Let be a complete metric space. Then every Cauchy sequence of elements from converges in . Suppose that is of the first category. Then there exists a countable collection of nowhere dense sets such that:
- Let . For each nowhere dense set , there exists a set such that .
- Let be a ball contained in such that . Let be a ball contained in whose radius is and such that . Repeat this process. For each let be a ball contained in whose radius is and such that and such that .
- The sequence is Cauchy since as gets large, the elements are very close. Since is a complete metric space, we must have that this Cauchy sequence therefore converges to some , i.e., .
- Now notice that for all because if not, then there exists an such that for all . Hence Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (\bar{B_n})^c} is open and so there exists an open ball Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle X} such that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x \in B \subset (\bar{B_n})^c} but then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \lim_{x \to \infty} x_n \neq x} because Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x_m \not \in B} for all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle m \geq n} .
- Since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x \in \bar{B_n}} for all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle n \in \mathbb{N}} then since Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle A_n \cap \bar{B_n} = \emptyset} we must have that then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x \not\in A_n }
Licensing
Content obtained and/or adapted from:
- The Baire Category Theorem, mathonline.wikidot.com under a CC BY-SA license