Difference between revisions of "Function Evaluation"
Jump to navigation
Jump to search
| Line 4: | Line 4: | ||
# Calculate the result. | # Calculate the result. | ||
</blockquote> | </blockquote> | ||
| + | |||
| + | '''Example''' | ||
| + | :Given the function <math> h(p) = p^2 + 2p </math>, evaluate <math> h(4) </math>. | ||
| + | |||
| + | To evaluate <math> h(4) </math>, we substitute the value 4 for the input variable <math>p</math> in the given function. | ||
| + | |||
| + | <div style="text-align: center;"><math> \begin{align} | ||
| + | h(p) & = p^2 + 2p\\ | ||
| + | h(4) & = (4)^2 + 2(4) \\ | ||
| + | & = 16 + 8 \\ | ||
| + | & = 24 \\ | ||
| + | \end{align} </math></div> | ||
| + | |||
== Resources == | == Resources == | ||
* [https://www.youtube.com/watch?v=E9YEUQR9NAU Evaluating Functions], Khan Academy | * [https://www.youtube.com/watch?v=E9YEUQR9NAU Evaluating Functions], Khan Academy | ||
* [https://courses.lumenlearning.com/waymakercollegealgebra/chapter/evaluate-and-solve-functions/ Evaluating and Solving Functions], Lumen Learning | * [https://courses.lumenlearning.com/waymakercollegealgebra/chapter/evaluate-and-solve-functions/ Evaluating and Solving Functions], Lumen Learning | ||
Revision as of 14:58, 12 January 2022
- HOW TO: EVALUATE A FUNCTION GIVEN ITS FORMULA
- Replace the input variable in the formula with the value provided.
- Calculate the result.
Example
- Given the function Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle h(p) = p^2 + 2p } , evaluate .
To evaluate , we substitute the value 4 for the input variable in the given function.
Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align} h(p) & = p^2 + 2p\\ h(4) & = (4)^2 + 2(4) \\ & = 16 + 8 \\ & = 24 \\ \end{align} }
Resources
- Evaluating Functions, Khan Academy
- Evaluating and Solving Functions, Lumen Learning
