Difference between revisions of "Laplace Transform to ODEs"
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| − | + | The Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions. | |
First consider the following property of the Laplace transform: | First consider the following property of the Laplace transform: | ||
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:<math>\mathcal{L}\{f''\}=s^2\mathcal{L}\{f\}-sf(0)-f'(0)</math> | :<math>\mathcal{L}\{f''\}=s^2\mathcal{L}\{f\}-sf(0)-f'(0)</math> | ||
| − | One can prove by | + | One can prove by induction that |
:<math>\mathcal{L}\{f^{(n)}\}=s^n\mathcal{L}\{f\}-\sum_{i=1}^{n}s^{n-i}f^{(i-1)}(0)</math> | :<math>\mathcal{L}\{f^{(n)}\}=s^n\mathcal{L}\{f\}-\sum_{i=1}^{n}s^{n-i}f^{(i-1)}(0)</math> | ||
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:<math>f^{(i)}(0)=c_i</math> | :<math>f^{(i)}(0)=c_i</math> | ||
| − | Using the | + | Using the linearity of the Laplace transform it is equivalent to rewrite the equation as |
:<math>\sum_{i=0}^{n}a_i\mathcal{L}\{f^{(i)}(t)\}=\mathcal{L}\{\phi(t)\}</math> | :<math>\sum_{i=0}^{n}a_i\mathcal{L}\{f^{(i)}(t)\}=\mathcal{L}\{\phi(t)\}</math> | ||
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:<math>\mathcal{L}\{f(t)\}=\frac{\mathcal{L}\{\phi(t)\}+\sum_{i=1}^{n}\sum_{j=1}^{i}a_is^{i-j}c_{j-1}}{\sum_{i=0}^{n}a_is^i}</math> | :<math>\mathcal{L}\{f(t)\}=\frac{\mathcal{L}\{\phi(t)\}+\sum_{i=1}^{n}\sum_{j=1}^{i}a_is^{i-j}c_{j-1}}{\sum_{i=0}^{n}a_is^i}</math> | ||
| − | The solution for ''f''(''t'') is obtained by applying the | + | The solution for ''f''(''t'') is obtained by applying the inverse Laplace transform to <math>\mathcal{L}\{f(t)\}.</math> |
Note that if the initial conditions are all zero, i.e. | Note that if the initial conditions are all zero, i.e. | ||
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:<math>f(t)=\frac{1}{8}\sin(2t)-\frac{t}{4}\cos(2t)</math> | :<math>f(t)=\frac{1}{8}\sin(2t)-\frac{t}{4}\cos(2t)</math> | ||
| + | |||
| + | == Laplace Transform to Systems of ODEs == | ||
| + | View an example from [https://tutorial.math.lamar.edu/classes/de/SystemsLaplace.aspx Laplace Transforms, Paul's Online Notes] | ||
==Licensing== | ==Licensing== | ||
Content obtained and/or adapted from: | Content obtained and/or adapted from: | ||
* [https://en.wikipedia.org/wiki/Laplace_transform_applied_to_differential_equations Laplace transform applied to ODEs, Wikipedia] under a CC BY-SA license | * [https://en.wikipedia.org/wiki/Laplace_transform_applied_to_differential_equations Laplace transform applied to ODEs, Wikipedia] under a CC BY-SA license | ||
Latest revision as of 12:25, 27 November 2021
The Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions.
First consider the following property of the Laplace transform:
One can prove by induction that
Now we consider the following differential equation:
with given initial conditions
Using the linearity of the Laplace transform it is equivalent to rewrite the equation as
obtaining
Solving the equation for and substituting with one obtains
The solution for f(t) is obtained by applying the inverse Laplace transform to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathcal{L}\{f(t)\}.}
Note that if the initial conditions are all zero, i.e.
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f^{(i)}(0)=c_i=0\quad\forall i\in\{0,1,2,...\ n\}}
then the formula simplifies to
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(t)=\mathcal{L}^{-1}\left\{{\mathcal{L}\{\phi(t)\}\over\sum_{i=0}^{n}a_is^i}\right\}}
An example
We want to solve
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f''(t)+4f(t)=\sin(2t)}
with initial conditions f(0) = 0 and f′(0)=0.
We note that
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi(t)=\sin(2t)}
and we get
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathcal{L}\{\phi(t)\}=\frac{2}{s^2+4}}
The equation is then equivalent to
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle s^2\mathcal{L}\{f(t)\}-sf(0)-f'(0)+4\mathcal{L}\{f(t)\}=\mathcal{L}\{\phi(t)\}}
We deduce
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathcal{L}\{f(t)\}=\frac{2}{(s^2+4)^2}}
Now we apply the Laplace inverse transform to get
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f(t)=\frac{1}{8}\sin(2t)-\frac{t}{4}\cos(2t)}
Laplace Transform to Systems of ODEs
View an example from Laplace Transforms, Paul's Online Notes
Licensing
Content obtained and/or adapted from:
- Laplace transform applied to ODEs, Wikipedia under a CC BY-SA license