Difference between revisions of "Applications of Integrals"

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(Created page with " * Average value of a function * Area between curves * Distance, velocity, acceleration * Volume * Work * Arc length * Surface area * Center of mass * Hydrostatic pressure and...")
 
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==Area between two curves==
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Suppose we are given two functions <math>y_1=f(x)</math> and <math>y_2=g(x)</math> and we want to find the area between them on the interval <math>[a,b]</math> . Also assume that <math>f(x)\ge g(x)</math> for all <math>x</math> on the interval <math>[a,b]</math> . Begin by partitioning the interval <math>[a,b]</math> into <math>n</math> equal subintervals each having a length of <math>\Delta x=\frac{b-a}{n}</math> . Next choose any point in each subinterval, <math>x_i^*</math> . Now we can 'create' rectangles on each interval. At the point <math>x_i*</math> , the height of each rectangle is <math>f(x_i^*)-g(x_i^*)</math> and the width is <math>\Delta x</math> . Thus the area of each rectangle is <math>\bigl[f(x_i^*)-g(x_i^*)\bigr]\Delta x</math> . An ''approximation'' of the area, <math>A</math> , between the two curves is
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:<math>A:=\sum_{i=1}^n \Big[f(x_i^*)-g(x_i^*)\Big]\Delta x</math> .
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Now we take the limit as <math>n</math> approaches infinity and get
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:<math>A=\lim_{n\to\infty}\sum_{i=1}^n \Big[f(x_i^*)-g(x_i^*)\Big]\Delta x</math>
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which gives the exact area. Recalling the definition of the definite integral we notice that
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:<math>A=\int\limits_a^b \bigl(f(x)-g(x)\bigr)dx</math> .
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This formula of finding the area between two curves is sometimes known as applying integration with respect to the ''x''-axis since the rectangles used to approximate the area have their bases lying parallel to the ''x''-axis. It will be most useful when the two functions are of the form <math>y_1=f(x)</math> and <math>y_2=g(x)</math> . Sometimes however, one may find it simpler to integrate with respect to the ''y''-axis. This occurs when integrating with respect to the ''x''-axis would result in more than one integral to be evaluated. These functions take the form <math>x_1=f(y)</math> and <math>x_2=g(y)</math> on the interval <math>[c,d]</math> . Note that <math>[c,d]</math> are values of <math>y</math> . The derivation of this case is completely identical. Similar to before, we will assume that <math>f(y)\ge g(y)</math> for all <math>y</math> on <math>[c,d]</math> . Now, as before we can divide the interval into <math>n</math> subintervals and create rectangles to approximate the area between <math>f(y)</math> and <math>g(y)</math> . It may be useful to picture each rectangle having their 'width', <math>\Delta y</math> , parallel to the ''y''-axis and 'height', <math>f(y_i^*)-g(y_i^*)</math> at the point <math>y_i^*</math>, parallel to the ''x''-axis. Following from the work above we may reason that an ''approximation'' of the area, <math>A</math> , between the two curves is
 +
:<math>A:=\sum_{i=1}^n \Big[f(y_i^*)-g(y_i^*)\Big]\Delta y</math> .
 +
As before, we take the limit as <math>n</math> approaches infinity to arrive at
 +
:<math>A=\lim_{n\to\infty}\sum_{i=1}^n \Big[f(y_i^*)-g(y_i^*)\Big]\Delta y</math> ,
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which is nothing more than a definite integral, so
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:<math>A=\int\limits_c^d \bigl(f(y)-g(y)\bigr)dy</math> .
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Regardless of the form of the functions, we basically use the same formula.
  
* Average value of a function
+
[[File:Closed path integral defined.png|Closed_path_integral_defined]]
* Area between curves
 
* Distance, velocity, acceleration
 
* Volume
 
* Work
 
* Arc length
 
* Surface area
 
* Center of mass
 
* Hydrostatic pressure and force
 
* Probability
 
  
 
==Resources==
 
==Resources==
 +
* [https://en.wikibooks.org/wiki/Calculus/Area Area], Wikibooks: Calculus
 
* [https://tutorial.math.lamar.edu/classes/calci/intappsintro.aspx Applications of Integrals - Cal I], Paul's Online Notes
 
* [https://tutorial.math.lamar.edu/classes/calci/intappsintro.aspx Applications of Integrals - Cal I], Paul's Online Notes
 
* [https://tutorial.math.lamar.edu/classes/calcii/intappsintro.aspx Applications of Integrals - Cal II], Paul's Online Notes
 
* [https://tutorial.math.lamar.edu/classes/calcii/intappsintro.aspx Applications of Integrals - Cal II], Paul's Online Notes

Revision as of 14:01, 15 October 2021

Area between two curves

Suppose we are given two functions and and we want to find the area between them on the interval . Also assume that for all on the interval . Begin by partitioning the interval into equal subintervals each having a length of . Next choose any point in each subinterval, . Now we can 'create' rectangles on each interval. At the point , the height of each rectangle is and the width is . Thus the area of each rectangle is . An approximation of the area, , between the two curves is

.

Now we take the limit as approaches infinity and get

which gives the exact area. Recalling the definition of the definite integral we notice that

.

This formula of finding the area between two curves is sometimes known as applying integration with respect to the x-axis since the rectangles used to approximate the area have their bases lying parallel to the x-axis. It will be most useful when the two functions are of the form and . Sometimes however, one may find it simpler to integrate with respect to the y-axis. This occurs when integrating with respect to the x-axis would result in more than one integral to be evaluated. These functions take the form and on the interval . Note that are values of . The derivation of this case is completely identical. Similar to before, we will assume that for all on . Now, as before we can divide the interval into subintervals and create rectangles to approximate the area between and . It may be useful to picture each rectangle having their 'width', , parallel to the y-axis and 'height', at the point , parallel to the x-axis. Following from the work above we may reason that an approximation of the area, , between the two curves is

.

As before, we take the limit as approaches infinity to arrive at

,

which is nothing more than a definite integral, so

.

Regardless of the form of the functions, we basically use the same formula.

Closed_path_integral_defined

Resources