Difference between revisions of "Laplace Transform to ODEs"
(Created page with "In mathematics, the Laplace transform is a powerful integral transform used to switch a function from the time domain to the Laplace transform#s-domain equiv...") |
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− | + | The Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions. | |
First consider the following property of the Laplace transform: | First consider the following property of the Laplace transform: | ||
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:<math>\mathcal{L}\{f''\}=s^2\mathcal{L}\{f\}-sf(0)-f'(0)</math> | :<math>\mathcal{L}\{f''\}=s^2\mathcal{L}\{f\}-sf(0)-f'(0)</math> | ||
− | One can prove by | + | One can prove by induction that |
:<math>\mathcal{L}\{f^{(n)}\}=s^n\mathcal{L}\{f\}-\sum_{i=1}^{n}s^{n-i}f^{(i-1)}(0)</math> | :<math>\mathcal{L}\{f^{(n)}\}=s^n\mathcal{L}\{f\}-\sum_{i=1}^{n}s^{n-i}f^{(i-1)}(0)</math> | ||
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:<math>f^{(i)}(0)=c_i</math> | :<math>f^{(i)}(0)=c_i</math> | ||
− | Using the | + | Using the linearity of the Laplace transform it is equivalent to rewrite the equation as |
:<math>\sum_{i=0}^{n}a_i\mathcal{L}\{f^{(i)}(t)\}=\mathcal{L}\{\phi(t)\}</math> | :<math>\sum_{i=0}^{n}a_i\mathcal{L}\{f^{(i)}(t)\}=\mathcal{L}\{\phi(t)\}</math> | ||
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:<math>\mathcal{L}\{f(t)\}=\frac{\mathcal{L}\{\phi(t)\}+\sum_{i=1}^{n}\sum_{j=1}^{i}a_is^{i-j}c_{j-1}}{\sum_{i=0}^{n}a_is^i}</math> | :<math>\mathcal{L}\{f(t)\}=\frac{\mathcal{L}\{\phi(t)\}+\sum_{i=1}^{n}\sum_{j=1}^{i}a_is^{i-j}c_{j-1}}{\sum_{i=0}^{n}a_is^i}</math> | ||
− | The solution for ''f''(''t'') is obtained by applying the | + | The solution for ''f''(''t'') is obtained by applying the inverse Laplace transform to <math>\mathcal{L}\{f(t)\}.</math> |
Note that if the initial conditions are all zero, i.e. | Note that if the initial conditions are all zero, i.e. |
Revision as of 10:21, 29 October 2021
The Laplace transform is a powerful integral transform used to switch a function from the time domain to the s-domain. The Laplace transform can be used in some cases to solve linear differential equations with given initial conditions.
First consider the following property of the Laplace transform:
One can prove by induction that
Now we consider the following differential equation:
with given initial conditions
Using the linearity of the Laplace transform it is equivalent to rewrite the equation as
obtaining
Solving the equation for and substituting Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle f^{(i)}(0)} with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle c_i} one obtains
The solution for f(t) is obtained by applying the inverse Laplace transform to
Note that if the initial conditions are all zero, i.e.
then the formula simplifies to
An example
We want to solve
with initial conditions f(0) = 0 and f′(0)=0.
We note that
- Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \phi(t)=\sin(2t)}
and we get
The equation is then equivalent to
We deduce
Now we apply the Laplace inverse transform to get
Licensing
Content obtained and/or adapted from:
- Laplace transform applied to ODEs, Wikipedia under a CC BY-SA license