Difference between revisions of "Abstract Algebra: Groups"
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<p>Clearly <span class="math-inline"><math>a * (b * c) \neq (a * b) * c</math></span> so <span class="math-inline"><math>\mathbb{Z}</math></span> does not form a group under the operation <span class="math-inline"><math>*</math></span>.</p> | <p>Clearly <span class="math-inline"><math>a * (b * c) \neq (a * b) * c</math></span> so <span class="math-inline"><math>\mathbb{Z}</math></span> does not form a group under the operation <span class="math-inline"><math>*</math></span>.</p> | ||
| − | ===Cancellation Law | + | ==Basic Theorems Regarding Groups== |
| + | <p>Recall that a group <span class="math-inline"><math>(G, \cdot)</math></span> is a set <span class="math-inline"><math>G</math></span> with a binary operation <span class="math-inline"><math>\cdot</math></span> such that:</p> | ||
| + | <ul> | ||
| + | <li><strong>1)</strong> <span class="math-inline"><math>\cdot</math></span> is associative, i.e., for all <span class="math-inline"><math>a, b, c \in G</math></span>, <span class="math-inline"><math>a \cdot (b \cdot c) = (a \cdot b) \cdot c)</math></span>.</li> | ||
| + | </ul> | ||
| + | <ul> | ||
| + | <li><strong>2)</strong> There exists an identity element <span class="math-inline"><math>e \in G</math></span> such that <span class="math-inline"><math>a \cdot e = a = e \cdot a</math></span> for all <span class="math-inline"><math>a \in G</math></span>.</li> | ||
| + | </ul> | ||
| + | <ul> | ||
| + | <li><strong>3)</strong> For each <span class="math-inline"><math>a \in G</math></span> there exists an <span class="math-inline"><math>a^{-1} \in G</math></span> such that <span class="math-inline"><math>a \cdot a^{-1} = a^{-1} \cdot a = e</math></span>.</li> | ||
| + | </ul> | ||
| + | <p>We will now look at some rather basic results regarding groups which we can derive from the group axioms above.</p> | ||
| + | <blockquote style="background: white; border: 1px solid black; padding: 1em;"> | ||
| + | <td><strong>Proposition 1:</strong> Let <span class="math-inline"><math>(G, \cdot)</math></span> be a group and let <span class="math-inline"><math>e</math></span> be the identity for this group. Then:<br /> | ||
| + | <strong>a)</strong> The identity element <span class="math-inline"><math>e \in G</math></span> is unique.<br /> | ||
| + | <strong>b)</strong> For each <span class="math-inline"><math>a \in G</math></span>, the corresponding inverse <span class="math-inline"><math>a^{-1} \in G</math></span> is unique.<br /> | ||
| + | <strong>c)</strong> For each <span class="math-inline"><math>a \in G</math></span>, <span class="math-inline"><math>(a^{-1})^{-1} = a</math></span>.<br /> | ||
| + | <strong>d)</strong> For all <span class="math-inline"><math>a, b \in G</math></span>, <span class="math-inline"><math>(a \cdot b)^{-1} = b^{-1} \cdot a^{-1}</math></span>.<br /> | ||
| + | <strong>e)</strong> For all <span class="math-inline"><math>a, b \in G</math></span>, if <span class="math-inline"><math>a \cdot b = e</math></span> then <span class="math-inline"><math>a = b^{-1}</math></span> and <span class="math-inline"><math>b = a^{-1}</math></span>.<br /> | ||
| + | <strong>f)</strong> If <span class="math-inline"><math>a^2 = a</math></span> then <span class="math-inline"><math>a = e</math></span>.</td> | ||
| + | </blockquote> | ||
| + | <ul> | ||
| + | <li><strong>Proof of a)</strong> Suppose that <span class="math-inline"><math>e</math></span> and <span class="math-inline"><math>e'</math></span> are both identities for <span class="math-inline"><math>\cdot</math></span>. Then:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad e = e \cdot e = e \cdot e' = e' \cdot e' = e' \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li>Therefore <span class="math-inline"><math>e = e'</math></span> so the identity for <span class="math-inline"><math>\cdot</math></span> is unique. <span class="math-inline"><math>\blacksquare</math></span></li> | ||
| + | </ul> | ||
| + | <ul> | ||
| + | <li><strong>Proof of b)</strong> Suppose that <span class="math-inline"><math>a^{-1} \in G</math></span> and <span class="math-inline"><math>a^{-1'} \in G</math></span> are both inverses for <span class="math-inline"><math>a \in G</math></span> under <span class="math-inline"><math>\cdot</math></span>. Then:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad a^{-1} = a^{-1} \cdot e = a^{-1} \cdot (a \cdot a^{-1'}) = (a^{-1} \cdot a)*a^{-1} = e \cdot a^{-1'} = a^{-1'} \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li>Therefore <span class="math-inline"><math>a^{-1} = a^{-1'}</math></span> so the inverse for <span class="math-inline"><math>a</math></span> is unique. <span class="math-inline"><math>\blacksquare</math></span></li> | ||
| + | </ul> | ||
| + | <ul> | ||
| + | <li><strong>Proof of c)</strong> Let <span class="math-inline"><math>a \in G</math></span>. Then <span class="math-inline"><math>(a^{-1})^{-1}</math></span> is the inverse to <span class="math-inline"><math>a^{-1}</math></span>. However, the inverse to <span class="math-inline"><math>a^{-1}</math></span> is <span class="math-inline"><math>a</math></span> and by (b) we have shown that the inverse of each element in <span class="math-inline"><math>G</math></span> is unique. Therefore <span class="math-inline"><math>a = (a^{-1})^{-1}</math></span>. <span class="math-inline"><math>\blacksquare</math></span></li> | ||
| + | </ul> | ||
| + | <ul> | ||
| + | <li><strong>Proof of d)</strong> If we apply the operation <span class="math-inline"><math>\cdot</math></span> between <span class="math-inline"><math>b^{-1} \cdot a^{-1}</math></span> and <span class="math-inline"><math>(a \cdot b)</math></span> we get:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad (a \cdot b) \cdot [b^{-1} \cdot a^{-1}] & = a \cdot [(b \cdot b^{-1}) \cdot a^{-1}] \\ \quad &= a \cdot [e \cdot a^{-1}] \\ \quad &= a \cdot a^{-1} \\ \quad &= e \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li>Therefore the inverse of <span class="math-inline"><math>(a \cdot b)</math></span> is <span class="math-inline"><math>b^{-1} \cdot a^{-1}</math></span>. We also have that the invere of <span class="math-inline"><math>(a \cdot b)</math></span> is <span class="math-inline"><math>(a \cdot b)^{-1}</math></span>. By (b), the inverse of <span class="math-inline"><math>(a \cdot b)</math></span> is unique and so:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad (a \cdot b)^{-1} = b^{-1} \cdot a^{-1} \quad \blacksquare \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li><strong>Proof of e)</strong> Suppose that <span class="math-inline"><math>a \cdot b = e</math></span>. Then:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad a \cdot b &= e \\ \quad (a \cdot b) \cdot b^{-1} &= e \cdot b^{-1} \\ \quad a \cdot (b \cdot b^{-1}) &= b^{-1} \\ \quad a \cdot e &= b^{-1} \\ \quad a &= b^{-1} \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li>Similarly:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad a \cdot b &= e \\ \quad a^{-1} \cdot (a \cdot b) &= a^{-1} \cdot e \\ \quad (a^{-1} \cdot a) \cdot b &= a^{-1} \\ \quad e \cdot b &= a^{-1} \\ \quad b &= a^{-1} \quad \blacksquare \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li><strong>Proof of f)</strong> Suppose that <span class="math-inline"><math>a^2 = a \cdot a = a</math></span>. Then:</li> | ||
| + | </ul> | ||
| + | <div style="text-align: center;"><math>\begin{align} \quad a^2 &= a \\ \quad a \cdot a &= a \\ \quad a^{-1} \cdot (a \cdot a) &= a^{-1} \cdot a \\ \quad (a^{-1} \cdot a) \cdot a &= e \\ \quad e \cdot a &= e \\ \quad a &= e \end{align}</math></div> | ||
| + | <ul> | ||
| + | <li>Hence <span class="math-inline"><math>a = e</math></span>. Alternatively we see that if <span class="math-inline"><math>a \cdot a = a</math></span> then the inverse of <span class="math-inline"><math>a</math></span> with respect to <span class="math-inline"><math>\cdot</math></span> is <span class="math-inline"><math>e</math></span>, that is <span class="math-inline"><math>a^{-1} = e</math></span>. Multiplying both sides of this equation by <span class="math-inline"><math>a</math></span> gives us that <span class="math-inline"><math>a = e</math></span>. <span class="math-inline"><math>\blacksquare</math></span></li> | ||
| + | </ul> | ||
| + | |||
| + | |||
| + | ==Cancellation Law== | ||
<p>We will now look at another important property of groups called the cancellation law.</p> | <p>We will now look at another important property of groups called the cancellation law.</p> | ||
<blockquote style="background: white; border: 1px solid black; padding: 1em;"> | <blockquote style="background: white; border: 1px solid black; padding: 1em;"> | ||
Revision as of 14:05, 19 November 2021
Recall that an operation on is said to be associative if for all we have that and is said to be commutative if for all we have that .
An element is the identity element of under if for all we have that and .
We can now begin to describe our first type of algebraic structures known as groups, which are a set equipped with a binary operation that is associative, contains an identity element, and contains inverse elements under for each element in .
Definition: A Group is a pair where is a set and is a binary operation on with the following properties:
1. For all , (Associativity of ).
2. There exists an such that for all , and (The existence of an Identity Element).
3. For all there exists an such that and (The existence of inverses).
Furthermore, if is a finite set then the group is said to be a Finite Group and if is an infinite set then the group is said to be an Infinite Group. More generally, the Order of (or **Size of ) is the size of and is denoted .
When we use the multiplication symbol to denote the operation on , we often call a “multiplicative group”. When the operation of the group is instead denoted by (instead of ) then we often call an “additive group”, and we write the inverse of each as (instead of ).
Some of the sets and binary operations we have already seen can be considered groups. For example, is a group under standard addition since the sum of any two real numbers is a real number, , is associative, an additive identity exists and inverse elements exist for every (namely ).
Furthermore, is also a group under the operation of standard addition since the sum of any two integers is an integer, addition is associative, the additivity identity is , and for all we have as additive inverses.
We will examine many other (more interesting) groups later on, but for now, let's look at an example of a set and a binary operation that does NOT form a group.
Example 1
Consider the set of integers and define for all by:
(Where the on the righthand side is usual addition of numbers). We will show that is NOT a group by showing that is not associative. Let . Then is not associative since:
Clearly so Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \mathbb{Z}} does not form a group under the operation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle *} .
Basic Theorems Regarding Groups
Recall that a group Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (G, \cdot)} is a set Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle G} with a binary operation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} such that:
- 1) Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} is associative, i.e., for all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a, b, c \in G} , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot (b \cdot c) = (a \cdot b) \cdot c)} .
- 2) There exists an identity element Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e \in G} such that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot e = a = e \cdot a} for all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} .
- 3) For each Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} there exists an Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} \in G} such that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot a^{-1} = a^{-1} \cdot a = e} .
We will now look at some rather basic results regarding groups which we can derive from the group axioms above.
Proposition 1: Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (G, \cdot)} be a group and let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e} be the identity for this group. Then:
a) The identity element Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e \in G} is unique.
b) For each Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} , the corresponding inverse Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} \in G} is unique.
c) For each Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a^{-1})^{-1} = a} .
d) For all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a, b \in G} , Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)^{-1} = b^{-1} \cdot a^{-1}} .
e) For all Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a, b \in G} , if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot b = e} then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a = b^{-1}} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b = a^{-1}} .
f) If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^2 = a} then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a = e} .
- Proof of a) Suppose that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e'} are both identities for . Then:
- Therefore Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e = e'} so the identity for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} is unique. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \blacksquare}
- Proof of b) Suppose that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} \in G} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1'} \in G} are both inverses for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} under Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} . Then:
- Therefore Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} = a^{-1'}} so the inverse for Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} is unique. Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \blacksquare}
- Proof of c) Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \in G} . Then Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a^{-1})^{-1}} is the inverse to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1}} . However, the inverse to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1}} is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} and by (b) we have shown that the inverse of each element in Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle G} is unique. Therefore Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a = (a^{-1})^{-1}} . Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \blacksquare}
- Proof of d) If we apply the operation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} between Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b^{-1} \cdot a^{-1}} and Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)} we get:
- Therefore the inverse of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)} is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b^{-1} \cdot a^{-1}} . We also have that the invere of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)} is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)^{-1}} . By (b), the inverse of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (a \cdot b)} is unique and so:
- Proof of e) Suppose that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot b = e} . Then:
- Similarly:
- Proof of f) Suppose that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^2 = a \cdot a = a} . Then:
- Hence Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a = e} . Alternatively we see that if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot a = a} then the inverse of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} with respect to Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle e} , that is Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} = e} . Multiplying both sides of this equation by Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} gives us that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a = e} . Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \blacksquare}
Cancellation Law
We will now look at another important property of groups called the cancellation law.
Theorem 1 (The Cancellation Law for Groups): Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (G, \cdot)} be a group and let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a, b, c \in G} . If Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot b = a \cdot c} or Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b \cdot a = c \cdot a} then .
- Proof: Let Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a^{-1} \in G} denote the inverse of Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a} under Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} . Suppose that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot b = a \cdot c} . Then:
- Similarly, suppose now that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b \cdot a = c \cdot a} . Then:
It is very important to note that the cancellation law holds with regards to the operation Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} for any group Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle (G, \cdot)} . We will see that the cancellation law does not necessarily hold with respect to an operation on a set when we look at algebraic structures with two defined operations.
It is also important to note that if Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle a \cdot b = c \cdot a} or Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b \cdot a = a \cdot c} then we cannot necessarily deduce that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle b = c} because we would then require the additional property that Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \cdot} is commutative which is not one of the group axioms (but instead one of the Abelian group axioms).