Difference between revisions of "Integration by Substitution"
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<p>The tricky part is trying to identify what you want to make your '''<i>u</i>''' to be. Some times substitution will not be enough and you will have to use the rules for integration by parts. That will be covered in a different section</p> | <p>The tricky part is trying to identify what you want to make your '''<i>u</i>''' to be. Some times substitution will not be enough and you will have to use the rules for integration by parts. That will be covered in a different section</p> | ||
+ | |||
+ | ====Steps==== | ||
+ | :{| | ||
+ | |<math>\int\limits_{x=a}^{x=b}f(x)dx</math> | ||
+ | |<math>=\int\limits_{x=a}^{x=b} f(x)\ \frac{du}{du}\ dx</math> | ||
+ | |style="padding-left: 20px"|(1) | ||
+ | |i.e. <math>\frac{du}{du}=1</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{x=a}^{x=b}{\left(f(x)\ \frac{dx}{du}\right)\left(\frac{du}{dx}\right)}\ dx</math> | ||
+ | |style="padding-left: 20px"|(2) | ||
+ | |i.e. <math>\frac{dx}{du}\cdot\frac{du}{dx}=1</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{x=a}^{x=b}\left(f(x)\ \frac{dx}{du}\right)g'(x)\ dx</math> | ||
+ | |style="padding-left: 20px"|(3) | ||
+ | |i.e. <math>\frac{du}{dx}=g'(x)</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{x=a}^{x=b}h(g(x))g'(x)dx</math> | ||
+ | |style="padding-left: 20px"|(4) | ||
+ | |i.e. Now equate <math>\left(f(x)\ \frac{dx}{du}\right)</math> with <math>h(g(x))</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{x=a}^{x=b}h(u)g'(x)dx</math> | ||
+ | |style="padding-left: 20px"|(5) | ||
+ | |i.e. <math>g(x)=u</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{u=g(a)}^{u=g(b)}h(u)du</math> | ||
+ | |style="padding-left: 20px"|(6) | ||
+ | |i.e. <math>du=\frac{du}{dx}dx=g'(x)dx</math> | ||
+ | |- | ||
+ | | | ||
+ | |<math>=\int\limits_{u=c}^{u=d}h(u)du</math> | ||
+ | |style="padding-left: 20px"|(7) | ||
+ | |i.e. We have achieved our desired result | ||
+ | |} | ||
<p>'''Ex. 1'''</p> | <p>'''Ex. 1'''</p> | ||
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<p><math>\int_{-1}^{2} \sqrt {x^2+4} (2x) \operatorname {d}x</math></p> | <p><math>\int_{-1}^{2} \sqrt {x^2+4} (2x) \operatorname {d}x</math></p> | ||
− | |||
− | |||
==Resources== | ==Resources== |
Revision as of 12:31, 6 October 2021
Integration by Substitution
There is a theorem that will help you with substitution for integration. It is called Change of Variables for Definite Integrals.
what the theorem looks like is this
In order to get you must plug a into the function g and to get you must plug b into the function g.
The tricky part is trying to identify what you want to make your u to be. Some times substitution will not be enough and you will have to use the rules for integration by parts. That will be covered in a different section
Steps
(1) i.e. (2) i.e. (3) i.e. (4) i.e. Now equate with (5) i.e. (6) i.e. (7) i.e. We have achieved our desired result
Ex. 1
Instead of making this a big polynomial we will just use the substitution method.
Step 1
Identify your u
Let
Step 2
Identify
Step 3
Now we plug in our limits of integration to our u to find our new limits of integration
When
and when
Now our integration problem looks something like this
Step 4
write your new integration problem
When we plug in our u it looks like
Step 5
Evaluate the Integral
As you can see this all simplified fairly nice. Using substitution will be hard, for most people, at first. Once you get the hang of doing this it should come to you faster and faster each time.
I'll give you some other problems to work on as well.
Ex. 2
Ex. 3
Resources
Example 1. Produced by Professor Zachary Sharon, UTSA
Example 2. Produced by TA Catherine Sporer, UTSA
Indefinite Integrals Using Substitution
- Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Integration by Substitution Part 1 by James Sousa, Math is Power 4U
- Integration by Substitution Part 2 by James Sousa, Math is Power 4U
- Ex 1: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 2: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 3: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 4: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 5: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 6: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 7: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 8: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 9: Indefinite Integration Using Substitution by James Sousa, Math is Power 4U
- Integration using U-Substitution by patrickJMT
- U-Substitution - More Complicated Examples by patrickJMT
- U-Substitution Example 1 by Krista King
- U-Substitution Example 2 by Krista King
- U-Substitution Example 3 by Krista King
- U-Substitution Example 4 by Krista King
- U-Substitution Example 5 by Krista King
- U-Substitution Example 6 by Krista King
- U-Substitution Example 7 by Krista King
- How To Integrate Using U-Substitution by The Organic Chemistry Tutor
Definite Integrals Using Substitution
- Definite Integration Using Subsitution by James Sousa, Math is Power 4U
- Ex 1: Definite Integration Using Substitution - Change Limits of Integration? by James Sousa, Math is Power 4U
- Ex 2: Definite Integration Using Substitution - Change Limits of Integration? by James Sousa, Math is Power 4U
- Ex 1: Definite Integration Using Substitution by James Sousa, Math is Power 4U
- Ex 2: Definite Integration Using Substitution by James Sousa, Math is Power 4U
- Integration by U-Substitution, Definite Integral by patrickJMT
- U-Substitution: When Do I Have to Change the Limits of Integration ? by patrickJMT
- U-Substitution Integration, Indefinite & Definite Integral by The Organic Chemistry Tutor