Baire's Theorem and Applications
Jump to navigation
Jump to search
The Baire Category Theorem
Lemma 1: Let be a topological space and let . If is a nowhere dense set then for every there exists a such that .
Theorem 1 (The Baire Category Theorem): Every complete metric space is of the second category.
- Proof: Let be a complete metric space. Then every Cauchy sequence of elements from converges in . Suppose that is of the first category. Then there exists a countable collection of nowhere dense sets such that:
- Let . For each nowhere dense set , there exists a set such that .
- Let be a ball contained in such that . Let be a ball contained in whose radius is and such that . Repeat this process. For each let be a ball contained in whose radius is and such that and such that .
- The sequence is Cauchy since as gets large, the elements are very close. Since is a complete metric space, we must have that this Cauchy sequence therefore converges to some , i.e., .
- Now notice that for all because if not, then there exists an such that for all . Hence is open and so there exists an open ball such that but then because for all .
- Since for all then since we must have that then
Licensing
Content obtained and/or adapted from:
- The Baire Category Theorem, mathonline.wikidot.com under a CC BY-SA license