Systems of Equations in Three Variables

See Systems of Equations in Two Variables for more information on systems of equations.

Examples

One solution: $x+y+z=3$ , $2x-3y+z=0$ , and $-5x-5y+23z=13$ . $x+y+z=3\implies 5x+5y+5z=15$ . We can add this to the third equation to get $28z=28$ , which means z = 1. So, the first two equations can be rewritten as $x+y=2$ and $2x-3y=-1$ . Using substitution, elimination, or graphing, we can calculate that x = 1 and y = 1 with these two equations. Thus, the solution to the system is (x, y, z) = (1, 1, 1).