Example 1
Evaluate the integral
Solution
Substitute . Then and we have
Applying the formula with we obtain
Example 2
Evaluate Failed to parse (unknown function "\dx"): {\displaystyle \int \frac{4-x}{\sqrt{16-x^2}}\dx }
.
Solution
This integral requires two different methods to evaluate it. We get to those methods by splitting up the integral:
Failed to parse (unknown function "\dx"): {\displaystyle \int \frac{4-x}{\sqrt{16-x^2}}\ dx = \int \frac{4}{\sqrt{16-x^2}}\ dx - \int \frac{x}{\sqrt{16-x^2}}\dx }
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The first integral is handled straightforward; the second integral is handled by substitution, with . We handle each separately.
: Set , so . We have
Combining these together, we have
Resources
Integration into Inverse trigonometric functions using Substitution by The Organic Chemistry Tutor
Integrating using Inverse Trigonometric Functions by patrickJMT