Arc Length

From Department of Mathematics at UTSA
Revision as of 14:00, 1 October 2021 by Lila (talk | contribs)
Jump to navigation Jump to search

We can deduce that the length of a curve with parametric equations , should be:

Since vector functions are fundamentally parametric equations with directions, we can utilize the formula above into the length of a space curve.

Arc length of a space curve

If the curve has the vector equation , or, equivalently, the parametric equations , where are continuous, then the length of the curve from to is:

}}

For those who prefer simplicity, the formula can be rewritten into:

or Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \quad\frac{dL}{dt}=|\mathbf{r}'(t)|}

Example Problem

Find the circumference of the circle given by the parametric equations Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle x(t)=R\cos(t),y(t)=R\sin(t)} , with Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle t\in[0,2\pi]} .

Failed to parse (MathML with SVG or PNG fallback (recommended for modern browsers and accessibility tools): Invalid response ("Math extension cannot connect to Restbase.") from server "https://wikimedia.org/api/rest_v1/":): {\displaystyle \begin{align}s&=\int\limits_0^{2\pi}\sqrt{\left(\tfrac{d}{dt}\big(R\cos(t)\big)\right)^2+\left(\tfrac{d}{dt}\big(R\sin(t)\big)\right)^2}dt\\ &=\int\limits_0^{2\pi}\sqrt{\big(-R\sin(t)\big)^2+\big(R\cos(t)\big)^2}dt\\ &=\int\limits_0^{2\pi}\sqrt{R^2\big(\sin^2(t)+\cos^2(t)\big)}dt\\ &=\int\limits_0^{2\pi}Rdt\\ &=R\cdot t\Big|_0^{2\pi}\\ &=\mathbf{2\pi R}\end{align}}

Resources