Recall that an operation on is said to be associative if for all we have that and is said to be commutative if for all we have that .
An element is the identity element of under if for all we have that and .
We can now begin to describe our first type of algebraic structures known as groups, which are a set equipped with a binary operation that is associative, contains an identity element, and contains inverse elements under for each element in .
Definition: A Group is a pair where is a set and is a binary operation on with the following properties:
1. For all , (Associativity of ).
2. There exists an such that for all , and (The existence of an Identity Element).
3. For all there exists an such that and (The existence of inverses).
Furthermore, if is a finite set then the group is said to be a Finite Group and if is an infinite set then the group is said to be an Infinite Group. More generally, the Order of (or **Size of ) is the size of and is denoted .
When we use the multiplication symbol to denote the operation on , we often call a “multiplicative group”. When the operation of the group is instead denoted by (instead of ) then we often call an “additive group”, and we write the inverse of each as (instead of ).
Some of the sets and binary operations we have already seen can be considered groups. For example, is a group under standard addition since the sum of any two real numbers is a real number, , is associative, an additive identity exists and inverse elements exist for every (namely ).
Furthermore, is also a group under the operation of standard addition since the sum of any two integers is an integer, addition is associative, the additivity identity is , and for all we have as additive inverses.
We will examine many other (more interesting) groups later on, but for now, let's look at an example of a set and a binary operation that does NOT form a group.
Example 1
Consider the set of integers and define for all by:
(Where the on the righthand side is usual addition of numbers). We will show that is NOT a group by showing that is not associative. Let . Then is not associative since:
Clearly so does not form a group under the operation .