Difference between revisions of "Finding Roots of an Equation"

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In mathematics, the roots of a function are the x-values that make y = 0. For example, the roots of the polynomial <math> y = x^2 - 4 </math> are 2 and -2, since <math> 0 = x^2 - 4 \implies 0 = (x - 2)(x + 2) \implies x = -2, 2</math>. The roots of <math> y = \frac{(2x - 5)(3 - x)}{x(x^2 + 1)} </math> are 3 and 5/2, since only the numerator needs to equal 0 for y to equal 0. The roots of <math> y = \frac{(x^2 - 4)(x-1)}{(x-2)} are -2 and 1. Note that 2 is not a root of this function since it makes both the denominator and numerator 0 (not just the numerator), and 0/0 is undefined.
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==Resources==
 
==Resources==
In mathematics, the roots of a function are the x-values that make y = 0. For example, the roots of the polynomial <math> y = x^2 - 4 </math> are 2 and -2, since <math> 0 = x^2 - 4 \implies 0 = (x - 2)(x + 2) \implies x = -2, 2</math>.
 
 
* [https://www.freemathhelp.com/finding-roots/#:~:text=A%20root%20is%20a%20value,f%20(%20x%20)%20%3D%200%20. Finding Roots], Free Math Help
 
* [https://www.freemathhelp.com/finding-roots/#:~:text=A%20root%20is%20a%20value,f%20(%20x%20)%20%3D%200%20. Finding Roots], Free Math Help

Revision as of 16:18, 17 September 2021

In mathematics, the roots of a function are the x-values that make y = 0. For example, the roots of the polynomial are 2 and -2, since . The roots of are 3 and 5/2, since only the numerator needs to equal 0 for y to equal 0. The roots of <math> y = \frac{(x^2 - 4)(x-1)}{(x-2)} are -2 and 1. Note that 2 is not a root of this function since it makes both the denominator and numerator 0 (not just the numerator), and 0/0 is undefined.

Resources