Difference between revisions of "The Additivity Theorem"

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<li>Hence <span class="math-inline"><math>\int_a^b f(x) \: d \alpha (x)</math></span> exists and:</li>
 
<li>Hence <span class="math-inline"><math>\int_a^b f(x) \: d \alpha (x)</math></span> exists and:</li>
 
</ul>
 
</ul>
<div style="text-align: center;"><math>\begin{align} \quad \int_a^b f(x) \: d \alpha (x) = \int_a^c f(x) \: d \alpha (x) + \int_c^b f(x) \: d \alpha (x) \quad \blacksquare \end{al
+
<div style="text-align: center;"><math>\begin{align} \quad \int_a^b f(x) \: d \alpha (x) = \int_a^c f(x) \: d \alpha (x) + \int_c^b f(x) \: d \alpha (x) \quad \blacksquare \end{align}</math></div>

Revision as of 15:54, 9 November 2021

The Additivity Theorem for Riemann Integrable Functions: Let be a real-valued function on the interval , and let . Then, is Riemann integrable on if and only if it is also Riemann integrable on and . In this case,

  • Proof: Suppose that Failed to parse (syntax error): {\displaystyle \int_a^c f(x) \: d \alpha (x) = A} and Failed to parse (syntax error): {\displaystyle \int_c^b f(x) \: d \alpha (x) = B} for some . Let be given.
    • Since Failed to parse (syntax error): {\displaystyle \int_a^c f(x) \: d \alpha (x) = A} we have that for there exists a partition Failed to parse (unknown function "\mathscr"): {\displaystyle P_{\epsilon_1} \in \mathscr{P}[a, c]} such that for all partitions Failed to parse (unknown function "\mathscr"): {\displaystyle P' \in \mathscr{P}[a, c]} finer than , () and for any choice of 's in each subinterval we have that:
    • Similarly, since Failed to parse (syntax error): {\displaystyle \int_c^b f(x) \: d \alpha (x) = B} we have that for there exists a partition Failed to parse (unknown function "\mathscr"): {\displaystyle P_{\epsilon_2} \in \mathscr{P}[c, b]} such that for all partitions Failed to parse (unknown function "\mathscr"): {\displaystyle P'' \in \mathscr{P}[c, b]} finer than , ) and for any choice of 's in each subinterval we have that:
    • Let . Then is a partition of and for all partitions Failed to parse (unknown function "\mathscr"): {\displaystyle P \in \mathscr{P}[a, b]} finer than , () we must have that and hold. Then for any choice of 's in each subinterval we have that:
    • Hence Failed to parse (syntax error): {\displaystyle \int_a^b f(x) \: d \alpha (x)} exists and:
    Failed to parse (unknown function "\begin{align}"): {\displaystyle \begin{align} \quad \int_a^b f(x) \: d \alpha (x) = \int_a^c f(x) \: d \alpha (x) + \int_c^b f(x) \: d \alpha (x) \quad \blacksquare \end{align}}