The First Derivative Test

The definition of a derivatives tells us that a derivative is the slope of the tangent line at a point on the function.

Derivatives can also tell us if a function is decreasing or increasing at a point.

A function $f(x)$ is increasing on an interval, if for two numbers $x_{1}$ and $x_{2}$ in the interval $x_{1}<x_{2},$ that $f(x_{1})<f(x_{2})$ is true.

A function $f(x)$ is decreasing on an interval, if for two numbers $x_{1}$ and $x_{2}$ in the interval $x_{1}<x_{2},$ that $f(x_{1})>f(x_{2})$ is true.

If a function $f(x)$ is continuous on a closed interval $[a,b],$ and differentiable on an open interval $(a,b),$ then the following applies:

1. If $f'(x)>0$ for all $x$ in $(a,b),$ then $f(x)$ is increasing on $[a,b].$

2. If $f'(x)<0$ for all $x$ in $(a,b),$ then $f(x)$ is decreasing on $[a,b].$

3. If $f'(x)=0$ for all $x$ in $(a,b),$ then $f(x)$ is constant on $[a,b].$

In the last section, we learned about absolute minimums/maximums. Inside a function, other extrema, known as relative extrema, can exist.

The relative extrema of a function are points on a function that are lower or higher than all of the points near them. Such points create "hills" or "valleys" within a given function.

Relative extrema occur at points on a function where the derivative at that point changes from increasing to decreasing, or decreasing to increasing.

If the derivative changes from increasing to decreasing, that point is known as a relative maximum.

If the derivative changes from decreasing to increasing, that point is known as a relative minimum.

By finding the relative extrema of a function, you can then calculate whether or not those extrema are relative minima or maxima using the derivative of the function at those points.

Relative extrema are always critical points of a function.

Example

Find the relative extrema of $f(x)=x^{3}-{\frac {3}{2}}x^{2}.$

First, check if the function is continuous for all $x.$

We can see the function exists for all $x$ therefore, it is continuous.

Second, find the critical numbers of $f(x)$ by using the derivative of the function.

Find the critical numbers by setting $f'(x)=0.$

$f'(x)=3x^{2}-3x$

$3x^{2}-3x=0$

$x(3x-3)=0$

$x=0,1.$

Third, create intervals with your critical numbers.

Since we have two critical numbers, we will have three intervals. They are:

$-\infty <x<0,0<x<1,1<x<\infty .$

Fourth, determine if $f'(x)$ is increasing or decreasing over each interval. Do this by evaluating a test number within each interval.

In most cases, it is beneficial to create a table to arrange the present data.

Interval	$-\infty <x<0$	$0<x<1$	$1<x<\infty$
Test Value	$x=-1$	$x={\frac {1}{2}}$	$x=2$
Sign of $f'(x)$	$f'(-1)=6$	$f'({\frac {1}{2}})={\frac {-3}{4}}$	$f'(2)=6$
Increasing/Decreasing	Increasing	Decreasing	Increasing

Lastly, determine if any relative maximums or minimums are present.

Since $f'(x)$ changes from increasing to decreasing to increasing, we can conclude that there is a relative maximum at $x=0,$ and a relative minimum at $x=1.$